<u>Answer:
</u>
The difference of (12f - 8g + 3h) -(4f – g + 5h) is 8f - 7g - 2h
<u>Solution:
</u>
From question given that the expression is
(12f - 8g + 3h) - (4f – g + 5h)
We have to find the difference of both the expressions.
By removing the parenthesis the above equation becomes,
12f - 8g + 3h - 4f + g - 5h
Separate the terms of f, g and h in above equation,
12f - 4f - 8g + g + 3h - 5h
On simplifying the above expression,
8f - 7g - 2h
Hence difference of (12f - 8g + 3h) - (4f – g + 5h) is 8f - 7g - 2h
Answer:
The minimum sample size needed for use of the normal approximation is 50.
Step-by-step explanation:
Suitability of the normal distribution:
In a binomial distribution with parameters n and p, the normal approximation is suitable is:
np >= 5
n(1-p) >= 5
In this question, we have that:
p = 0.9
Since p > 0.5, it means that np > n(1-p). So we have that:





The minimum sample size needed for use of the normal approximation is 50.
That’s a Very good question