Answer:
-7+12 will also give u 5 with a positive sign
Answer:
As Given △QRS is rotated about point P to △Q′R′S′ .
As we know after rotation by any angle of pre-image neither the shape nor size of the image changes, the image after rotation is congruent to pre image.
Out of the options given
→The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.
→The corresponding angle measurements in each triangle between the pre-image and the image are preserved.
are true.
Answer:

Step-by-step explanation:
<u>Similar Triangles</u>
Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.
Considering the triangle PQR, the sum of its internal angles must be 180°:

Substituting the known values:

Solving for R:


Angles S and Q are congruent, thus

Angles T and R are congruent, thus

Summarizing:

Answer:
-1/2
Step-by-step explanation:
The equation for slope is (y2-y1)/(x2-x1).
Plug in the values given in the problem
(11-7)/((-2)-6)
Then simplify
4/(-8)=-1/2
Answer:
C. 24 ft.
Step-by-step explanation:
There is a right triangle which can be drawn in side the pyramid with height h, hypotenuse 25 ft and bas = 1/2 * 14 = 7.
So using Pythagoras:
25^2 = h^2 + 7^2
h^2 = 25^2 - 7^2
h^2 = 576
h = √576 = 24 ft.