The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x
<h3>Trigonometric ratios</h3>
It is important to note that
sin A = opposite/ hypotenuse
cos A = adjacent/ hypotenuse
Then,
opposite =
Hypotenuse =
Let's find the adjacent side using the Pythagorean theroem
cos A = x/hypotenuse
cos A = √(1 + x²)/ (1 - x²) /√1 + x
Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x
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Answer:
x = - 1 ± 2i
Step-by-step explanation:
we can use the discriminant b² - 4ac to determine the nature of the roots
• If b² - 4ac > , roots are real and distinct
• If b² - 4ac = 0, roots are real and equal
• If b² - ac < 0, roots are not real
for x² + 2x + 5 = 0
with a = 1, b = 2 and c = 5, then
b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16
since b² - 4ac < 0 there are 2 complex roots
using the quadratic formula to calculate the roots
x = ( - 2 ± ) / 2
= (- 2 ± 4i ) / 2 = - 1 ± 2i
Answer:
Step-by-step explanation:
1. Use the distributive property
5 ( x - 7 ) = 6 ( x + 2 ) → 5x - 35 = 6x + 12
2. Subtract 5x from both sides of the equation
5x - 5x -35 = 6x - 5x + 12 → -35 = x + 12
3. Subtract 12 from both sides
-35 - 12 = x + 12 - 12 → -47 = x
4. So, the answer is
