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RUDIKE [14]
3 years ago
12

100000000000 to the 10th power

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

The answer for this question is 1e+110

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The length of a rectangle is 13 centimeters more than its width
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What do you mean by this question

8 0
3 years ago
Angle α lies in quadrant II , and tanα=−125 . Angle β lies in quadrant IV , and cosβ=35 .
Artist 52 [7]

Answer:

cos(\alpha+\beta)=\frac{33}{65}

Step-by-step explanation:

step 1

Find cos α

we know that

tan^2(\alpha)+1=sec^2(\alpha)

we have

tan(\alpha)=-\frac{12}{5}

substitute

(-\frac{12}{5})^2+1=sec^2(\alpha)

sec^2(\alpha)=\frac{144}{25}+1

sec^2(\alpha)=\frac{169}{25}

sec(\alpha)=\pm\frac{13}{5}

Remember that Angle α lies in quadrant II

so

sec α is negative

sec(\alpha)=-\frac{13}{5}

Find the value of cos α

cos)\alpha)=\frac{1}{sec(\alpha)}

so

cos(\alpha)=-\frac{5}{13}

step 2

Find sin α

we know that

tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}

sin(\alpha)=tan(\alpha)cos(\alpha)

we have

tan(\alpha)=-\frac{12}{5}

cos(\alpha)=-\frac{5}{13}

substitute

sin(\alpha)=(-\frac{12}{5})(-\frac{5}{13})

sin(\alpha)=\frac{12}{13}

step 3

Find sin β

we know that

sin^2(\beta)+cos^2(\beta)=1

we have

cos(\beta)=\frac{3}{5}

substitute

sin^2(\beta)+(\frac{3}{5})^2=1

sin^2(\beta)=1-(\frac{3}{5})^2

sin^2(\beta)=1-\frac{9}{25}

sin^2(\beta)=\frac{16}{25}

sin(\beta)=\pm\frac{4}{5}

Remember that

Angle β lies in quadrant IV

so

sin β is negative

sin(\beta)=-\frac{4}{5}

step 4

Find cos(α−β)

we know that

cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)

we have

cos(\alpha)=-\frac{5}{13}

cos(\beta)=\frac{3}{5}

sin(\alpha)=\frac{12}{13}

sin(\beta)=-\frac{4}{5}

substitute the given values

cos(\alpha+\beta)=(-\frac{5}{13})(\frac{3}{5})-(\frac{12}{13})(-\frac{4}{5})

cos(\alpha+\beta)=(-\frac{15}{65})+(\frac{48}{65})

cos(\alpha+\beta)=\frac{33}{65}

7 0
4 years ago
Need helpp fastt plss will give brainliest to who is correct plss helpp
Citrus2011 [14]

Answer:

333 inches = 27.75 feet = 9.25 yards

6 0
3 years ago
PLEASE HELP ME!!!
Brums [2.3K]

Answer:

\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}

Step-by-step explanation:

5x^2-13x+7=0

x=\dfrac{13\pm \sqrt{169-140}}{10}=\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10} . Hope this helps!

8 0
3 years ago
Read 2 more answers
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