Question

NEED THESE ANSWERED ASAP SO I CAN GRADUATE THIS WEEK

Answer 1

For this case we must solve each of the equations proposed:

A) $-6 (2s-1) = 30$

We apply distributive property to the terms within parentheses:

$-12s + 6 = 30$

Subtracting 6 from both sides of the equation we have:

$-12s = 24$

Dividing between -12 on both sides of the equation:

$s = \frac {24} {- 12}s = -2$

B) $-3m = -5 (m-8)$

We apply distributive property to the terms within parentheses:

$-3m = -5m + 40$

We add 5m on both sides of the equation:

$2m = 40$

Dividing between 2 on both sides of the equation:

$m = \frac {40} {2}\\m = 20$

C) $7 (2-g) = 49$

We apply distributive property to the terms within parentheses:

$14-7g = 49$

We subtract 14 from both sides of the equation:

$-7g = 35$

Dividing between -7 on both sides of the equation:

$g = \frac {35} {- 7}\\g = -5$

D) -$7 (3w + 4) = 14$

We apply distributive property to the terms within parentheses:

$-21w-28 = 14$

We add 28 to both sides of the equation:

$-21w = 42$

Dividing between -21 on both sides of the equation:

$w = \frac {42} {- 21}\\w = -2$

Answer:

$s = -2\\m = 20\\g = -5\\w = -2$

Answer 2

This is all the answers hope this helps. if it does please mark brainliest