6 questions, 80 points
1 answer:
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(6y - 11)(6y + 11) = ay² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
Im assuming you are supposed to factor this problem considering there is no = sign. starting with numbers, you can factor, or divide, both of those numbers by 9. moving on to letters, both terms have a “y” attached to them, so you can take out a y as well. leaving you with the simplified equation being
9y (2x-3)
9y (2x-3)