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Gre4nikov [31]
3 years ago
11

PLEASE HELP ! WILL MARK BRAINLIEST !You have seven red marbles and seven blue marbles in a bag. You randomly take a marble from

the bag , and then you randomly take another marble from the bag without returning the first marble to the bag. What is the probability that both marbles are red?
Mathematics
2 answers:
katrin2010 [14]3 years ago
6 0

Answer:

P= 3/13

Step-by-step explanation:

R=7

B=7

Total=14

P(one red marble)=7/14=1/2

P(another red marble no replacement)=6/13

1/2 times 6/13=6/26=3/13

Molodets [167]3 years ago
5 0

Answer:

3/13

Step-by-step explanation:

7/14 * 6/13 = 3/13

Ok:

<h3>In the first round of picking a marble, the chance of getting red is 7 out of 14 [7/14]. In the second round, since you took a red marble before, taking red the second time will be 6 out of 13 marbles [6/13]. So we multiply the chances of red the first time by the chances of red the second time [ 7/14 * 6/13 ] and we get our answer that the chance of picking red both times... is 3/13. </h3><h3 /><h3>Hope you learn how to math from this! [and save you]</h3>
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If y is directly proportional to x square and y equal 1/8 when x = 1/2 what is the positive value of x when y it was 9/2?
mojhsa [17]

Answer:

d

Step-by-step explanation:

Given y is directly proportional to x² then the equation relating them is

y = kx² ← k is the constant of proportion

To find k use the condition y = \frac{1}{8} when x = \frac{1}{2}, then

\frac{1}{8} = k(\frac{1}{2} )² = \frac{1}{4} k ( multiply both sides by 8 )

1 = 2k ( divide both sides by 2 )

k = \frac{1}{2}

y = \frac{1}{2} x² ← equation of proportion

When y = \frac{9}{2} , then

\frac{9}{2} = \frac{1}{2} x² ( multiply both sides by 2 )

9 = x² ( take the square root of both sides )

x = ± \sqrt{9} = ± 3

with positive value x = 3 → d

8 0
3 years ago
36 to the power -1/2
IRISSAK [1]
0.166667
it was rounded
6 0
3 years ago
What is the theoretical probability of Eric picking a black marble next time based on Eric's results what is the experimental pr
o-na [289]
The answer is a! i dont promise
5 0
3 years ago
Describe the graph of the function. y = |x – 4| – 7
Lemur [1.5K]

Answer:

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x

Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Step-by-step explanation:

5 0
3 years ago
One step inequalities.... 9x&lt;18<br> how to solve
Nuetrik [128]
So 9x<18 can be factored out into 
9(x)<9(2)
you can divide both sides by 9
x<2 

so the solution is any number more than 2, but not 2
5 0
2 years ago
Read 2 more answers
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