Question

PLEASE HELP ! WILL MARK BRAINLIEST !You have seven red marbles and seven blue marbles in a bag. You randomly take a marble from the bag , and then you randomly take another marble from the bag without returning the first marble to the bag. What is the probability that both marbles are red?

Answer 1

Answer:

P= 3/13

Step-by-step explanation:

R=7

B=7

Total=14

P(one red marble)=7/14=1/2

P(another red marble no replacement)=6/13

1/2 times 6/13=6/26=3/13

Answer 2

Answer:

3/13

Step-by-step explanation:

7/14 * 6/13 = 3/13

Ok:

In the first round of picking a marble, the chance of getting red is 7 out of 14 [7/14]. In the second round, since you took a red marble before, taking red the second time will be 6 out of 13 marbles [6/13]. So we multiply the chances of red the first time by the chances of red the second time [ 7/14 * 6/13 ] and we get our answer that the chance of picking red both times... is 3/13.

Hope you learn how to math from this! [and save you]