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Vlada [557]
3 years ago
5

What is the sum of 1/9, 2/3,and 5/18? A.19/18 B.8/30 C.4/15 D.12/9

Mathematics
1 answer:
amm18123 years ago
8 0
1/9 times 2/2=2/18
2/3 times 6/6=12/18

2/18+12/18+5/18=(2+12+5)/18=19/18=1 and 1/8


A is answer
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What is 4^6 . 4^6 please help​
KonstantinChe [14]

Answer:

4^12 or 16777216

Step-by-step explanation:

4^6* 4^6

We can symplify 4^6* 4^6

Since they both have the same base, we can add there exponent:

4^6* 4^6= 4^12

4^12 equals to 16777216

8 0
3 years ago
This composite figure is made of two identical pyramids
Arisa [49]

Answer:

C. 2

Step-by-step explanation:

hope it answers your question ! if not lmk

6 0
2 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
1 and a 1/2 divided by 3/8
Musya8 [376]
1\frac{1}{2}:\frac{3}{8}=\ \ \ \ | make\ improper\ fractions\\\\&#10;\frac{3}{2}:\frac{3}{8}=\ \ \ \ \ \ | multiply\ first\ factor\ by\ inverse\ of\ the\ second\\\\&#10;\frac{3}{2}*\frac{8}{3}=\frac{3*8}{2*3}=\frac{8}{2}=4
5 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (4,-6) and (-2,3)
yarga [219]

Here is your answer and an explanation

Answer: y = -2/3x

Explanation:

This can be determined by calculating the gradient of the straight line, using:

m=ΔyΔx

=−6−34−(−2)

=−96

=−32

Then we use the slope-point form of the straight line:

y−y1=m(x−x1)

to give:

y−3=−32(x−(−2))

∴y−3=−32(x+2)

∴y−3=−32x−3

∴y=−32x

7 0
3 years ago
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