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3 years ago

If f(x)=1/x and g(x)=3x^2 what is f(g(x))

Mathematics

1 answer:

nika2105 [10]3 years ago

7 0

Answer:

$f(g(x))=\frac{1}{3x^2}$

Step-by-step explanation:

$f(g(x))\quad \textnormal{means put}\quad g \quad\textnormal{in to}\quad f$

$\therefore f(g(x))=\frac{1}{3x^2}$

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Need help find the missing term

Lerok [7]

Let me show u one in detail.

First we have to find the common ratio. We do this by dividing the second term by the first term.

ur first problem...
12/3 = 4...so the common ratio is 4

now we use the formula
an = a1 * r^(n-1)
n = term u want to find = 15
a1 = first term = 3
r = common ratio = 4
now we sub
a15 = 3 * 4^(15 - 1)
a15 = 3 * 4^14
a15 = 3 * 268435456
a15 = 805,306,368 <== ur 15th term

thats all there is to it...and, of course, u can always look on the internet for a geometric sequence calculator...to check urself...lol

7 0

4 years ago

Which of the following represents an example to calculate the sum of the numbers (accumulator)?A. number += numberB. total += nu

Hatshy [7]

Answer: The correct option would be,

B. total += number

Step-by-step explanation:

Since, the variable used to keep the running total is called sum of the numbers or accumulator,

Thus, accumulator = total + number,

i.e. we obtain accumulator by assigning total to total plus number.

Or, accumulator is,

total += number,

Hence, OPTION 'B' is correct.

3 0

3 years ago

(1+sint)/(cost)-(cost)/(1-sint)

Evgen [1.6K]

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)}{1-\sin(t)}$

Multiply through the second term by $1+\sin(t)$ :

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)}{1-\sin(t)}\cdot\dfrac{1+\sin(t)}{1+\sin(t)}$

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{1-\sin^2(t)}$

Recall that $\cos^2(x)+\sin^2(x)=1$ for all x :

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{\cos^2(t)}$

If $\cos(t)\neq0$ , we can cancel a factor of it in the second fraction.

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{1+\sin(t)}{\cos(t)}$

and this simplifies to

$\dfrac{(1+\sin(t))-(1+\sin(t))}{\cos(t)} = \boxed{0}$

8 0

3 years ago

I don't understand 17 or18 plz help I need it by tonight

jarptica [38.1K]

I got the answers hopefully okay #17 is 8 times 4 makes 32 biscuits so multiply 2x4 and you get 8 cups of flour #18 A is true B is false C is false and D is true

5 0

3 years ago

Callie bought a bag of dried fruit: cherries, pears, and apples.In the bag,1/4 of the dried fruit is cherries and 2/3 of the rem

goldenfox [79]

Answer:

There 24 pieces of Apples in the bag of dry fruit.

Step-by-step explanation:

Let the total number of dried fruit bought be 'x'.

Given:

1/4 of the dried fruit is cherries.

Hence Number of cherries = $\frac{1}{4}x$

Also Given:

2/3 of the remainder is pears.

Hence we can say Number of pears is equal to 2/3 times Total number of dried fruit minus Number of cherries.

Framing the equation we get;

Number of Pears = $\frac{2}{3} (x-\frac{1}{4}x) = \frac{2}{3} x- \frac{2}{12}x= \frac{2}{3} x- \frac{1}{6}x$

But Given:

Number of Pears = 48

Substituting the values we get;

$\frac{2}{3} x- \frac{1}{6}x= 48\\$

By taking L.C.M we get;

$\frac{2\times2}{3\times 2} x- \frac{1\times1}{6\times1}x= 48\\\\\frac{4}{6} x- \frac{1}{6}x= 48\\\\\frac{4x-x}{6}=48\\\\\frac{3x}{6}=48\\\\\frac{x}{2}=48\\\\x= 48\times2= 96$

Hence Total Number of Dry fruit = 96 pieces.

Number of cherries = $\frac{1}{4}x=\frac{1}{4} \times 96 = 24$

Now We need to find the Number of Pieces of Apples.

We know that Total Number of Pieces of dried fruit is equal to sum of Number of cherries and Number of Pears and Number of Apples.

Framing Equation we get

Number of Pieces of Apples= Total Number of Pieces of dried fruit - Number of cherries - Number of Pears = 96-48-24 =24 pieces

Hence There 24 pieces of Apples in the bag of dry fruit.

5 0

4 years ago