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Lynna [10]
3 years ago
15

Prove the following relations: 1) (1 - cos²A) (1 + tan²A) = tan²A​

Mathematics
2 answers:
krok68 [10]3 years ago
7 0

Step-by-step explanation:

So, this way we can do. Thank you!

liberstina [14]3 years ago
4 0

Step-by-step explanation:

(1 - cos²A) (1 + tan²A) = tan²A

(sin²A)(sec²A) = tan²A

(sin²A)(1/cos²A) = tan²A

(sin²A)/(cos²A) = tan²A

tan²A = tan²A → <u>Proved</u>

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Please help easy stuff.......
nataly862011 [7]

To evaluate a function at a given input, you have to substitute every occurrence of the variable with that particular value.

So, for the first function, you have

T(x) = -x-2 \implies T(-4) = -(-4)-2 = 4-2 = 2

The name of the variable is obviously irrelelvant, so the same goes for the second function:

w(x) = 14-6x \implies w(-3) = 14-6\cdot(-3) = 14 + 18 = 32

3 0
2 years ago
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If 32^2c=8^c what is the value of c? 1 2 3 5
Elina [12.6K]

Answer:

  • as written, c ≈ 0.000979 or c = 4
  • alternate interpretation: c = 0

Step-by-step explanation:

<em>As written</em>, you have an equation that cannot be solved algebraically.

  (32^2)c = 8^c

  1024c = 8^c

  1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero

A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.

___

If you mean ...

  32^(2c) = 8^c

  (2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2

  2^(10c) = 2^(3c) . . . . . . . simplify

  10c = 3c . . . . . . . . . . . . . .log base 2

  7c = 0 . . . . . . . . . . . . . . . subtract 3c

  c = 0 . . . . . . . . . . . . . . . . divide by 7

7 0
3 years ago
1.What is the value of log3 729?
xxMikexx [17]
I believe the value of log3 729 is 6

3 0
2 years ago
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16055 divided by 16?​
AveGali [126]

Answer:

1003.4375

Step-by-step explanation:

16055/16 is 1003.4375

8 0
2 years ago
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When 15 times a number is.
lubasha [3.4K]

Answer:

2

Step-by-step explanation:

15x + 16 = 48 - x

16x = 32

x = 2

Plug two in and it fits right in :)

8 0
3 years ago
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