The answer is (3,2). I did this by drawing a graph, inserting the two midpoints you provided, and put in each potential midpoint, finding (3,2) is the only midpoint that connects to the line.
Answer:
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 7.2 minutes and a standard deviation of 2.1 minutes.
This means that 
For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.
This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.
X = 9



has a pvalue of 0.8051
X = 3



has a pvalue of 0.0228
0.8051 - 0.0228 = 0.7823
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
I'll get you started. Let x and y be the two numbers. we have: x + y = 74 (sum is 74) x = 4y - 6 (the number x is six less than 4 times y) Now that you have the equations use an algebraic techniques to eliminate one variable thereby solving for the other. If you need more help add a comment to your question.
1/4 because 6/24 can be simplified all the way down to 1/4
Answer:
If a neutral object loses 1.5x106 electrons, then what will be its charge? ... Felect = (9x109 N/m2/C2)•(4.65 x 10-6 C)•(7.28 x 10-6 C)/(0.658 m)2 = 0.704 N.
Step-by-step explanation: