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3 years ago

Show me how to solve 384 divided by 55

Mathematics

1 answer:

sveticcg [70]3 years ago

8 0

Answer:

36R24 dont know if this is correct becuase i typed this out and i did not use my regular way becuase it typed it out and not write it in numbers

Step-by-step explanation:

ok its kind of hard to explain on a computer but I will try.

1. put the big number under the house and put the smallest number knocking on the door so (this is long division) in this case it would be 384 under the house and 55 knocking on the door.

2. you then ask your self how much times can 55 go in to 3 you be thinking I cant do that so you add a zero on top of the house (be sure to line up the place values) then ask your self how much times could 55 go in to 38 you may be thinking you cant do that either so you add a zero on top of the house then ask your self how much times can 55 go in to

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Sergio039 [100]

Answer:

0.5:1

Step-by-step explanation:

laps:minutes

So we can find how much Ronald runs in 2 minutes, by dividing 6:12 (or 6/12) by 6. This will give you 1:2 (One lap = 2 minutes).

But you're looking for 1 minute, so with 1:2, you have to divide them by 1/2, so it will be 0.5:1.

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Solve the following differential equation: (2x+5y)dx+(5x−4y)dy=0 *Hint: they are exact C=.

Tpy6a [65]

Answer with Step-by-step explanation:

The given differential equation is

$(2x+5y)dx+(5x-4y)dy=0$

Now the above differential equation can be re-written as

$P(x,y)dx+Q(x,y)dy=0$

Checking for exactness we should have

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial y}=\frac{\partial (2x+5y)}{\partial y}=5$

$\frac{\partial Q}{\partial x}=\frac{\partial (5x-4y)}{\partial x}=5$

As we see that the 2 values are equal thus we conclude that the given differential equation is exact

The solution of exact differential equation is given by

$u(x,y)=\int P(x,y)dx+\phi(y)\\\\u(x,y)=\int (2x+5y)dx+\phi (y)\\\\u(x,y)=x^2+5xy+\phi (y)$

The value of $\phi (y)$ can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

$\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c$

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Vadim26 [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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