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3 years ago

12

One line passes through the points (-3,-1) and (1,-9). Another line passes through point (1,4) and (5,6). Are the lines parallel

, perpendicular, or neither

1 answer:

amm18123 years ago

3 0

The lines are perpendicular.

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The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude is 6 m. Find the total surface area of

Eva8 [605]

Answer:

806.12 m

Step-by-step explanation:

<u>Step 1: Write the data</u>

<em>Side (s) = 12</em>

<em>Altitude (h) = 6</em>

<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>

<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>

<u>Step 3: Substitute values of 's' and 'h'</u>

<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>

Area = 806.12 m

Therefore, the total surface area of the pyramid is 806.12 m.

!!

4 0

3 years ago

A certain solution of salt water is 10% salt and weighs 50 pounds., More salt must be added to produce a solution that ls

SpyIntel [72]

what are do you want from me i don't even know my bad

5 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

Im just wasting points :) Ignore this

ollegr [7]

Why? how much points do you have to spare?

5 0

3 years ago

You have a hat with 5 gray, 3 red, 5 white, and 2 green marbles in it. Find the probability of picking a marble, replacing it, a

nordsb [41]

Answer:

100% chance. I don't know if you mean a certain color. We need to know that color if you want us to help you. But, if you really just want to pick a marble, replace it, and pick another, you will ALWAYS get a marble.

6 0

2 years ago