The volume of the ring-shaped remaining solid is <u>1797 cm³</u>.
The volume is the total space occupied by an object.
The volume of a sphere of radius r units is given as (4/3)πr³.
The volume of a cylinder with radius r units and height h units is given as πr²h.
In the question, we are asked to find the volume of the remaining solid when a sphere of radius 9cm is drilled by a cylindrical driller of radius 5cm.
The volume will be equal to the difference in the volumes of the sphere and cylinder, where the height of the cylinder will be taken as the diameter of the sphere (two times radius = 2*9 = 18) as it is drilled through the center.
Therefore, the volume of the ring-shaped remaining solid is given as,
= (4/3)π(9)³ - π(5)²(18) cm³,
= π{972 - 400} cm³,
= 572π cm³,
= 1796.99 cm³ ≈ 1797 cm³.
Therefore, the volume of the ring-shaped remaining solid is <u>1797 cm³</u>.
Learn more about volumes of solids at
brainly.com/question/14565712
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