Question

Use radical notation to write the expression. Simplify if possible. (-64) 2/3

Answer 1

Answer:

16

Step-by-step explanation:

we know that

$a^{\frac{n}{m}}=\sqrt[m]{a^{n}}$

In this problem we have

$(-64)^{\frac{2}{3}}$

therefore

$a=-64$

$n=2$

$m=3$

substitute

$(-64)^{\frac{2}{3}}=\sqrt[3]{(-64)^{2}}$

Remember that

$64=4^{3}$

substitute

$\sqrt[3]{(-4^{3})^{2}}=\sqrt[3]{(-4^{2})^{3}}=\sqrt[3]{(16)^{3}}=16$