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2 years ago

Draw the graph of linear equation 2x - 3y + 7 - 0) and hence find the coordinates of the point when the

Mathematics

1 answer:

kow [346]2 years ago

8 0

Answer:

The line crosses the x-axis at the point (-3.5,0).

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Please help me! im really stuck on this one!

Nataly_w [17]

Dependent variable. Its fairly easy if you plug in the problem into
:)

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3 years ago

How do you simplify -3 1/2- -12 1/4

astraxan [27]

To make the problem simpler, turn it to an improper fraction.

-7/2--49/48

-7/2+49/48

They have to have same dnominator to add.

-168/48+49/48

-119/48

8 0

4 years ago

The points (-6, r)<br> and<br> (6,3) lie on a line with slope 3/4. Find the missing coordinate r.

iren [92.7K]

Answer:

r=-6

Step-by-step explanation:

$m=\frac{y2-y1}{x2-x1} \\\frac{3-r}{6-(-6)} =\frac{3}{4} \\4(3-r)=3(12)\\12-4r=36\\-4r=24\\r=-6$

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3 years ago

Whats the greatest common factor of 13 and 26 .

Lera25 [3.4K]

2 x 13=26
1 x 26= 26
answer is 26

8 0

3 years ago

Read 2 more answers

Please helpppp it has to do with P(A U B)

Katyanochek1 [597]

$P(A)=0.5$ , $P(B)=0.6$ , $P(A\cup B)=0.8$

We find the probability of intersection using the inclusion/exclusion principle:

$P(A\cap B)=P(A)+P(B)-P(A\cup B)=0.3$

By definition of conditional probability,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{0.3}{0.6}=0.5$

For $A$ and $B$ to be independent, we must have

$P(A\cap B)=P(A)\cdot P(B)$

in which case we have $0.3=0.5\cdot0.6$ , which is true, so $A$ and $B$ are indeed independent.

Or, to establish independence another way, in terms of conditional probability, we must have

$P(A\mid B)\cdot P(B)=P(A)\cdot P(B)\implies P(A\mid B)=P(A)$

which is also true.

7 0

3 years ago