Answer:
49 cars
Step-by-step explanation:
Probability of cars to be sold in a week,a = 0.2
Probabiity of cars not sold in a week, b = 0.8
Number of cars estimated to be sold in a week = 20 and 60 cars in 3 weeks
Using, P(x) = nCx *(a)∧x * (b)∧n - x, where n = 3 weeks, x = 1 week
P(x=1) = 3C1 * (0.2) * (0.8)² = 3 X 0.2 X 0.64 X 60 cars = 23 cars
P(x=2) = 3C2 * (0.2)² * (0.8) = 3 X 0.04 X 0.8 X 60 cars = 6 cars
Number of cars three weeks from now: 20 + 23 + 6 = 49 cars
t + c = 32
0.80 t + 0.40 c = 18
Multiplying the first by 0.8
0.8 t + 0.8 c = 0.8 (32) = 25.6
Subtracting,
0.8 c - 0.40 c = 25.6 - 18
0.40 c = 7.6
c = 7.6/.4 = 19
Answer: 19 cans of corn
Check
t = 32-19 = 13
.8(13)+.4(19) = 18 good
2 + 83 = 85
The sum of the two primes, 2 and 83, is 85. The product of the two primes, 2 and 83, is 166.
2 × 83 = 166
Your final answer is 166.
Here is what the graphs will look like.