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Rudiy27
3 years ago
13

Find the volume of a cylinder that has a radius of 5 centimeters and a height of 3

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

first find the area of the circle face.

formula is pi x r²            (pi goes on for a long time, this is just rounded!)

so 3.14 x 25 = 78.5

now multiply this by the height

78.5 x 3 = 235.5cm³

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HELPPPPPPPP why is the answer D?
Marysya12 [62]
We can solve for x by raising both sides to the -3 power (which is the reciprocal of -1/3):

(c^-1/3)^-3 = x^-3
c^1=x^-3
c=x^-3

Since the exponent on the x is a negative, we have to move it to the denominator to make it positive:

c= 1/x³
8 0
3 years ago
Read 2 more answers
If line segment RU is considered the base of parallelogram RSTU, what is the corresponding height of the parallelogram?
klasskru [66]
Given that line segment RU with vertices R(1, 1) and U(4, 5) is considered the base of parallelogram RSTU.

Then, the line segment ST with vertices S(7, 0) and T(10, 4) is the top of the parallelogram.

The corresponding height of the parallelogram is the length of a line with endponts at RU and ST and perpendicular to both RU and ST.

The equation of the line segment RU is given by
\frac{y-1}{x-1} = \frac{5-1}{4-1} = \frac{4}{3}  \\  \\ 3(y-1)=4(x-1) \\  \\ 3y-3=4x-4 \\  \\ 3y=4x-1 \\  \\ y= \frac{4}{3} x- \frac{1}{3}

Recall that given that two lines are perpendicular, the product of the slope of the two lines is -1.
Let the slope of the line perpendicular to line RU be m, then
\frac{4}{3} m=-1 \\  \\ m=- \frac{3}{4}

Thus, the equation of the line perpendicular to RU passing through point (1, 1) is given by
y-1=- \frac{3}{4} (x-1) \\  \\ 4(y-1)=-3(x-1) \\  \\ 4y-4=-3x+3 \\  \\ 4y=-3x+7 \\  \\ y=- \frac{3}{4} x+ \frac{7}{4}

The equation of the line segment ST is given by
\frac{y-0}{x-7} = \frac{4-0}{10-7} = \frac{4}{3}  \\  \\ 3y=4(x-7)=4x-28 \\  \\ y= \frac{4}{3} x- \frac{28}{3}

The line perpendicular to line segment RU intersected line segment ST at the point given by
- \frac{3}{4} x+ \frac{7}{4}=\frac{4}{3} x- \frac{28}{3} \\  \\ \frac{4}{3} x+\frac{3}{4} x=\frac{7}{4}+\frac{28}{3} \\  \\  \frac{25}{12} x= \frac{133}{12}  \\  \\ x= \frac{133}{25}  \\  \\ y=\frac{4}{3} \left(\frac{133}{25}\right)- \frac{28}{3}= -\frac{56}{25}

Thus, the corresponding height of the parallelogram is the line with endpoints
(1,1) \ and \ \left(\frac{133}{25},-\frac{56}{25}\right)

Recall that the length of a line passing through points
(x_1,y_1) \ and \ (x_2,y_2)
is given by
l= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Thus, the length of the line passing through points
(1,1) \ and \ \left(\frac{133}{25},-\frac{56}{25}\right)
is given by
l= \sqrt{\left(\frac{133}{25}-1\right)^2+\left(-\frac{56}{25}-1\right)^2}  \\  \\ = \sqrt{\left( \frac{108}{25}\right)^2+\left(- \frac{81}{25} \right)^2}= \sqrt{ \frac{11,664}{625} + \frac{6,561}{625} }  \\  \\ = \sqrt{ \frac{729}{25} } = \frac{27}{5} =5.4

Therefore, <span>the corresponding height of the given parallelogram is 5.4 units</span>
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4 years ago
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Terri's teacher gives her the equation 3(5)^x=127-2x, and tells her that she will not know how to solve it algebraically. Explai
kicyunya [14]
3(5^x) is an exponential function.and which rise very fast
y = 127 - 2x is a line Which decrease wçith a 2 slope f(0) = 127
3.5^2 = 75 and 3.5^3 = 375
I guess the intersection will be between 2and 3
lets put both the functions in a graph calculator
window:
x between 2 and 3
y between 75 and 127
I have an intersection between 2 and 3
use the "table" of the calculator
we can see that the intersection is between 2.3 and 2.4
try again
range:
start:2.3
end 2.4
intersection is in [2.3;2.31]
lets say it's 2.305 



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How many cups of peaches does he need to make only 1 cup of fruit salad?

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