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omeli [17]
4 years ago
7

Write the expression (4x-2)*6(2x-7) in the standard form of a quadratic expression ax^2 +bx+c. What are the values of the coeffi

cients of each term and
the constant term. a=? b=? c=?
Mathematics
2 answers:
erma4kov [3.2K]4 years ago
8 0
So,

All we have to do is multiply out the terms.

(4x - 2)(6)(2x - 7)

Multiply the first and last terms (for no reason whatsoever).
(8x^2 - 32x + 14)(6)

Distribute the 6.
48x^2 - 192x + 84 (standard quadratic expression)

The standard form of a quadratic equation is:
ax^2 + bx + c

From this comparison, it is easy to see that a is 48, b is -192, and c is 84.  Notice that the negative/positive sign goes with each numerical coefficient.

So the values of the coefficients are 48, -192, and 84.
maw [93]4 years ago
6 0
Ok so we just expand
using distributive propety
a(b+c)=ab+ac
we can put the 6 to the side since multiplication is commmutative and assocative
(4x-2)(6)(2x-7)=6[(4x-2)(2x-7)]
we distribute the inner for ease

(4x-2)(2x-7)=
(4x-2)(2x)+(4x-2)(-7)=
(4x)(2x)+(-2)(2x)+(4x)(-7)+(-2)(-7)=
8x^2+-4x+-28x+14=
8x^2-32x+14
then times 6 the whole thing for all terms
48x^2-192x+84
ax^2+bx+c

a=48
b=-192
c=84
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How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80   (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2    x = /100 - 4y^2  (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
6 0
3 years ago
Please help me now plz
sergey [27]

Answer:

x=12

Step-by-step explanation:

The right side is a right triangle

The base is 1/2 of the bottom or 5

The height is x and the hypotenuse is 13

We can use the Pythagorean theorem

a^2 +b^2 = c^2

5^2 +x^2=13^2

25+x^2 = 169

Subtract 25 from each side

25-25+x^2 = 169-26

x^2 =144

Take the square root of each side

sqrt(x^2) = sqrt(144)

x= 12

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Step-by-step explanation:

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Step-by-step explanation:

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Find the value of x to the nearest tenth.<br> 9.0<br> 8.6<br> 26.3<br> 5.7
Ket [755]

Answer: x = 9.0

Step-by-step explanation:

From the given right angle triangle,

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With m∠39 as the reference angle,

the adjacent side of the right angle triangle is 7

The unknown side represents the opposite side of the right angle triangle.

To determine x, we would apply

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