Answer:
A campaign manager would like to show the distribution of individuals...
Step-by-step explanation:
goodness of fit can be used to compare observed and expected counts. The newspaper report would be the expected. The campaign manager's distribution is the expected.
11.
(87+91+86+x)/4=90.
x=96.
13.
50×y > 130.
the lowest number could be 3, because 50×2=120, which is less than 130.
12:7
12(2):7(2)
24:14
12:7 = 24:14
I hoped I helped(:
X^6= 3^12
(X^6) ^1/6. = (3^12)^1/6
X=9
The rule to remember for this problem is: i^2 = -1
(4 + i)(1 - 5i)
4 - 20i + i - 5i^2
4 - 19i + 5
9 - 19i