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zalisa [80]
3 years ago
11

Solve the inequality and graph the solution -10 >= -2z

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0
-10>=-2 the answer is >8
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In triangle PQR, Line QS and line SR are angle bisectors to angle P (74 degrees). How many Degrees are in the angle QSR.
AlexFokin [52]

we know that

<u>in the triangle PQR</u>

m∠PQR+m∠QPR+m∠QRP=180°------> the sum of the internal angles of a triangle is equal to 180 degrees

(m∠PQR+m∠QRP)+74°=180°-------> (m∠PQR+m∠QRP)=106°

we know that

If QS and SR are angle bisectors

then

<u>In the triangle QSR</u>

m∠SQR+m∠QSR+m∠QRS=180°-------> equation 1

and

(m∠SQR+m∠QRS)=106°/2--------> (m∠SQR+m∠QRS)=53°

substitute the value of (m∠SQR+m∠QRS)=53° in the equation 1

53°+m∠QSR=180°

m∠QSR=180°-53°-------->m∠QSR= 27°

therefore

<u>the answer is</u>

The measure of angle QSR is  27 degrees

4 0
4 years ago
Math simplify (7a+5b-2c) + (5a+7b) + (2a-7c) + (2a-5b+3c) algebra
Alekssandra [29.7K]

Answer:

-10a^2+25ab-15ac+12a+12b-2c

Step-by-step explanation:

(7a+5b-2c)+(5a+7b)+(2a-7c)+(2a-5b+3c)

Distribute:

=7a+5b-2c+5a+7b+(2a)(2a)+(2a)(-5)+(2a)(3c)+(-7a)(2a)+(-7a)(-5b)+(-7a)(3c)

=7a+5b-2c+5a+7b+4a^2-10ab+6ac-10a^2+35ab-21ac

Combine all like terms:

=(4a^2-14a^2)+(-10ab+35ab)+(6ac-21ac)+(7a+5a)+(5b+7b)+(-2c)

=-10a^2+25ab-15ac+12a+12b-2c

6 0
3 years ago
What is the answer to this question below guys.
Mashutka [201]

Answer:

Step-by-step explanation:

6+8=14

7 0
3 years ago
PLEASEEE HELPPPPPP!!
Korvikt [17]

Answer:

40c=120

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is my mystery number???
emmasim [6.3K]

Answer:

48 or 66

Step-by-step explanation:

Even numbers have digits that add to 12: 39, 48, 57, 66, 75.

48 and 66 are even and add up to 12.

5 0
3 years ago
Read 2 more answers
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