Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Answer:
x=-3, y=-6. (-3, -6).
Step-by-step explanation:
-4x+y=6
-5x-y=21
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-9x=27
x=27/-9
x=-3
-5(-3)-y=21
15-y=21
y=15-21
y=-6
-6×-6=36
f-34=36
34+36=70
f=70