Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
72°
Step-by-step explanation:
You correctly found x, but the measure of the angle is ...
4x-22 = 4·23.5-22 = 72°
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or (6x-69)° = (141-69)° = 72°
Answer:i dont know to do this stuff but i think you have to divide i think ???
Step-by-step explanation:
