The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.
The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:
They must be free from fractional terms.
Shouldn't have derivatives in any fraction.
The highest order term shouldn't be exponential, logarithmic or trigonometric function.
The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.
Therefore, the degree of the given differential equation is 1.
Multiple both ratios by a least common denominator the least common denominator for both is 15 multiply the first ratio by 3/3 9/15=9/15 both are equal because when multiplying by the least common denominator you get the same answer