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3 years ago

What is the degree of differential equation? ?

Mathematics

1 answer:

Delicious77 [7]3 years ago

6 0

Answer:

Degree = 1

Step-by-step explanation:

Given:

The differential equation is given as:

$\frac{d^2y}{dx^2}+(\frac{dy}{dx})^2+6y=0$

The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.

The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:

They must be free from fractional terms.

Shouldn't have derivatives in any fraction.

The highest order term shouldn't be exponential, logarithmic or trigonometric function.

The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.

Therefore, the degree of the given differential equation is 1.

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3 years ago

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3 years ago

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Misha Larkins [42]

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2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
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If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
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however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
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If you squared it you would get -1, which is defined
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and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
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Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.

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3 years ago

What is the equation for X+3y=16;(-3,-4)

Galina-37 [17]

I hope this helps you

-3+3. (-4)=16

-3-12=16

-15=16 false

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3 years ago

What is the degree of differential equation? ?​

What is the degree of differential equation? ?