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anastassius [24]
3 years ago
7

What is the degree of differential equation? ?​

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

Degree = 1

Step-by-step explanation:

Given:

The differential equation is given as:

\frac{d^2y}{dx^2}+(\frac{dy}{dx})^2+6y=0

The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.

The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:

  • They must be free from fractional terms.
  • Shouldn't have derivatives in any fraction.
  • The highest order term shouldn't be exponential, logarithmic or trigonometric function.

The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.

Therefore, the degree of the given differential equation is 1.

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Coleman uses his graphing calculator to find all of the solutions to the equation shown below.
Phoenix [80]

Answer:

The correct option is;

D. x = -1.38 and 0.82

Please find attached the combined function chart

Step-by-step explanation:

The given equation is x³ + 3 = -x⁴ + 4

Plotting the equation using Excel, we have;

f(x) = x³ + 3, h(x) = -x⁴ + 4

x                                             f(x)                                       h(x)

-1.4                                         0.256                                   0.1584

-1.39                                       0.314381                              0.26699

-1.38                                       0.371928                             0.373261

-1.37                                       0.428647                             0.477246

-1.36                                       0.484544                             0.57898

Which shows an intersection at the point around -1.38

x                                          f(x)                                     h(x)

0.77                                    3.456533                         3.64847

0.78                                    3.474552                         3.629849

0.79                                    3.493039                          3.610499

0.8                                         3.512                                3.5904

0.81                                      3.531441                           3.569533

0.82                                       3.551368                          3.547878

0.83                                       3.571787                            3.525417

Which shows the intersection point around 0.82

Therefore, the correct option is x = -1.38 and 0.82

From the graphing calculator the intersection point is given as

x = -1.3802775691 and 0.81917251339.

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