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Sonja [21]
3 years ago
12

In the given figure, angle APC =angle BQD. Prove that: AB //CD.​

Mathematics
1 answer:
aniked [119]3 years ago
3 0

1. <APC = <DQB [ Given]

2. Arc(AC = BD) [ Equal angles subtend equal arcs]

3. AB//CD [From 2]

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<h3>Answer: choice C) 15</h3>

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2(4+x)+(13+x)

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So the original equation

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3x+21 = 3x+k

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Subtract 3x from both sides

3x+21 = 3x+k

3x+21-3x = 3x+k-3x

21 = k

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If k = 21, then the original equation will have infinitely many solutions. This is because we will end up with 3x+21 on both sides, leading to 0 = 0 after getting everything to one side. This is a true equation no matter what x happens to be.

If k is some fixed number other than 21, then there will be no solutions. This equation is inconsistent (one side says one thing, the other side says something different). If k = 15, then

3x+21 = 3x+k

3x+21 = 3x+15

21 = 15 .... subtract 3x from both sides

The last equation is false, so there are no solutions here.

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Answer:

1 inch to 4: 12 to 28

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Step-by-step explanation:

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3 years ago
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