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kaheart [24]
3 years ago
10

Mrs. Henderson wants to put wallpaper border around her living room the room is 18 ft by 22 ft. How many feet of border are need

ed?
Mathematics
1 answer:
irga5000 [103]3 years ago
8 0
If I am understanding the question, and assuming the living room is a rectangle, then the border should be 80 ft
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Brooke saved the same amount of money each week for four weeks. She made this table to show how much money she saved.
Musya8 [376]

Answer:

In 10 weeks of time, Brooke would  earn $ 20.

Step-by-step explanation:

Here, according to the table:

The money saved in week 1   =  $ 2   =   $(1  x 2)

The money saved in week 2  =  $ 4   =  $ ( 2 x 2)

The money saved in week 3   =  $ 6  =  $ ( 3 x 2)

The money saved in week 4   =  $ 8 =   $ ( 4 x 2)

So, by the graph relation, we can see that:

The amount saved in n weeks = ( n x 2) dollars

So, the amount saved by Brooke in 10 weeks is:

Put n =  10, we get:

The money saved  = 2 n = 2 x 10 = $ 20

Hence, in 10 weeks of time, Brooke would  earn $ 20.

5 0
3 years ago
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
3 years ago
Can someone solve this?
aleksley [76]

Answer:

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

\cos \left(91^{\circ \:}\right)=-0.01745\dots

c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi

4 0
3 years ago
I REALLY NEED HELP ASAP<3 :)If the answer is not a whole number, it should be entered as a decimal rounded to the hundredths
Degger [83]
If her hourly rate stays the same, how many hours would she have<span> to work to earn $217 next week? ... She wants to enlarge the </span>photograph<span> so that its </span>width<span> is 10 in. ... Cross-Multiply: (4)(x)=(6)(10); Simplify: 4x=60; Divide both sides by 4 to find the height of the </span>new photograph<span>: \frac{4x}{4}=\frac{60}{4. Answer: 15 </span>inches<span> .</span>
8 0
3 years ago
An ac unit uses 3500 watts or power. If it runs for 10 hours each day and the utility company charges $0.13 per kWh, how much do
Helga [31]

Cost = (3500 W)·(1 kw/1000 W)·(10 hrs/day)·(30 day/month)·($0.13/kw-hr)

Cost = (3500·1·10·30·0.13 / 1000)·(W·kW·hr·da·$ / W·da·month·kw·hr)

Cost = <em> 136.50  $/month</em>

5 0
3 years ago
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