Rahul use addition property of equality in step 2.
Solution:
The image of the question is attached below.
Step 1:
combine like terms together.
To make the denominator same multiply and divide 2x by 5.
Step 2:
By addition property of equality, add 
on both side of the equation.
Step 3:
Step 4:
Multiply by 
on both side of the equation.
Hence Rahul use addition property of equality in step 2.
1 / 10 is the easiest answer. Remember ratios are just percentages. It could also be 2/20, 3/30, as long as it is 10%.
Her credits need to be AT LEAST EQUAL TO OR GREATER THAN 144 (credit hours) so we can eliminate choices B and D.
She already completed 4 semesters in which she receives 15 credit per semester.
This expression can be written as 4(15).
She needs to do a certain remaining hours of credit which can be represented by c and only c without any other coefficient.
So, the most reasonable choice here is A.
Answer:
666.67π .ft^3
<em>here's</em><em> your</em><em> solution</em>
<em>=</em><em>></em><em> </em><em>radius</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ft</em>
<em>=</em><em>></em><em> </em><em>height</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>ft</em>
<em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>πr^</em><em>2</em><em>h</em><em>/</em><em>3</em>
<em>=</em><em>></em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>radius</em><em> and</em><em> height</em><em> </em>
<em>=</em><em>></em><em> </em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>^</em><em>2</em><em>*</em><em>2</em><em>0</em><em>/</em><em>3</em><em>π</em>
<em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>6</em><em>6</em><em>6</em><em>.</em><em>6</em><em>7</em><em>π</em><em> </em><em>.</em><em>ft^</em><em>3</em>
<em>hope</em><em> it</em><em> helps</em>
Answer:
This question is asking you to find the ending position of a shape (particle) that is moving horizontally along the horizontal axis by finding its velocity with the equation shown. When t=0, the shape is 4 units to the left of the vertical axis, so it wants you to find where on the horizontal axis the shape is when t = 8. Hope this helped!!!
