<span>a= 2 ft/s^2
t=3 s
vi=4 ft/s
vf=?
One can use the kinematic equation: vf=vi+at
vf=(4 ft/s)+(2 ft/s^2)(3 s)= (4 ft/s)+(6 ft/s)=10 ft/s</span>
4.

5.

doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

</span>
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Minus 2 degrees every hour
there are 4 hours
d=degrees dropped
- 2 x 4 = d