<span>It would be 6 days because if you triple 4 that s 12 and 2 goes into 12, 6 times</span>
So,
We are trying to figure out when Grandpa Lopez's age was twice that of Dad.
Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.
66 + x = 2(37 + x)
Distribute.
66 + x = 74 + 2x
Subtract x from both sides.
66 = 74 + x
Subtract 74 from both sides.
-8 = x
So 8 years ago, G. Lopez was twice as old as Dad. Let's check that.
66 - 8 = 58
37 = 8 = 29
29 * 2 = 58
58 = 58
It checks.
Answer:
x = 1
Step-by-step explanation:
1/2x - 3/4 = 3/8 - 5/8x
The LCD is 8. Lets change every fraction to a denominator of 8.
4/8x - 6/8 = 3/8 - 5/8x
Now multiply both sides by 8.
4x - 6 = 3 - 5x
Add 5x to both sides. Add 6 to both sides.
9x = 9
Divide both sides by 9.
x = 1
R:{-46, 52}. You cannot repeat any numbers and the order is from least to greatest.
