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vlabodo [156]
3 years ago
10

\frac{(2xy^2)^5}{(4x^2y)^2 (xy^2)}" alt="\frac{(2xy^2)^5}{(4x^2y)^2 (xy^2)}" align="absmiddle" class="latex-formula">
Please solve this and also mention the steps
Mathematics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

2 y^6

Step-by-step explanation:

Simplify the following:

(2 x y^2)^5/((4 x^2 y)^2 x y^2)

Hint: | Distribute exponents over products in (4 x^2 y)^2.

Multiply each exponent in 4 x^2 y by 2:

(2 x y^2)^5/(4^2 x^(2×2) y^2 x y^2)

Hint: | Multiply 2 and 2 together.

2×2 = 4:

(2 x y^2)^5/(4^2 x^4 y^2 x y^2)

Hint: | Evaluate 4^2.

4^2 = 16:

(2 x y^2)^5/(16 x^4 y^2 x y^2)

Hint: | Distribute exponents over products in (2 x y^2)^5.

Multiply each exponent in 2 x y^2 by 5:

(2^5 x^5 y^(5×2))/(16 x^4 y^2 x y^2)

Hint: | Multiply 5 and 2 together.

5×2 = 10:

(2^5 x^5 y^10)/(16 x^4 y^2 x y^2)

Hint: | Compute 2^5 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

2^5 = 2×2^4 = 2 (2^2)^2:

(2 (2^2)^2 x^5 y^10)/(16 x^4 y^2 x y^2)

Hint: | Evaluate 2^2.

2^2 = 4:

(2×4^2 x^5 y^10)/(16 x^4 y^2 x y^2)

Hint: | Evaluate 4^2.

4^2 = 16:

(2×16 x^5 y^10)/(16 x^4 y^2 x y^2)

Hint: | Multiply 2 and 16 together.

2×16 = 32:

(32 x^5 y^10)/(16 x^4 y^2 x y^2)

Hint: | In (32 x^5 y^10)/(16 x^4 y^2 x y^2), divide 32 in the numerator by 16 in the denominator.

32/16 = (16×2)/16 = 2:

(2 x^5 y^10)/(x^4 y^2 x y^2)

Hint: | For all exponents, a^n a^m = a^(n + m). Apply this to (2 x^5 y^10)/(x^4 y^2 x y^2).

Combine powers. (2 x^5 y^10)/(x^4 y^2 x y^2) = 2 x^(5 - 1 - 4) y^(10 - 2 - 2):

2 x^(5 - 1 - 4) y^(10 - 2 - 2)

Hint: | Evaluate 5 - 1 - 4.

5 - 1 - 4 = 0:

2 x^0 y^(10 - 2 - 2)

Hint: | Evaluate 10 - 2 - 2.

10 - 2 - 2 = 6:

2 x^0 y^6

Hint: | Any nonzero expression to the zero power is one.

x^0 = 1:

2×1 y^6

Hint: | Simplify the expression.

Write 2×1 y^6 as 2 y^6:

Answer: 2 y^6

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