Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
The first one is (z-7)(z-1)
second: (x+1/3)(x+1/3)
third: (x-1/5)(x-1/5)
fourth: (x-5)(x-2)
Answer:
C. The y-intercept is (0, 4).
Step-by-step explanation:
The graph of f(x) = 4 is a straight line parallel to the x-axis passing through the point (0, 4).
Answer:
T<7
Step-by-step explanation:
21+7T+8<43
29+7T<43
7T<43‒29
7T<14
7T/7<14/7
T<7
i think it is clear &i hope it helps you