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Klio2033 [76]
3 years ago
10

Kai cuts out all the page numbers of a b\ook. He takes each number and cuts the numbers into separate digits (single digit numbe

rs are already separate). Given that the book has 999 pages numbered 1 through 999, how many separate digits does Kai have when he is finished
Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

2,889 digits

Step-by-step explanation:

Total pages of the book = 999 pages

Page 1 - 9 cut separately = 9 digits

Page 10 - 99 = 90 pages

Total digits = 2(90)

= 180 digits cut separately

Page 100 - 999 = 900 pages

Total digits = 3(900)

= 2,700 digits cut separately

how many separate digits does Kai have when he is finished

Total separate digits Kai have when he is finished = 9 digits + 180 digits + 2700 digits

= 2,889 digits

Total separate digits Kai have when he is finished = 2,889 digits

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I'm assuming you're trying to simplify the expression?
If so, start by combining like terms.
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That is the furthest you can simplify. If it had an equals sign, it would be an equation, and you would solve for x algebraically. But, since there is no equals sign, it is just an expression, and you simplify it to the best of your ability.
Hope this helps!
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What is the answer to this question someone help pls: Find three consecutive integers whose sum is -30
Cerrena [4.2K]

Answer:

  -11, -10, -9

Step-by-step explanation:

The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.

_____

I like to work "consecutive integer" problems using the average value of the integers involved. The average of <u>two</u> consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are <u>three</u> consecutive integers, so their average is the middle one.

If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...

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3 years ago
Which description of the vector shown is correct? O The magnitude is 777, and the direction angle is approximately 315º. The mag
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I think the typing of the answer options must have some typos.

the magnitude of a vector is the length of the vector.

the length of the vector is Pythagoras over its coordinates.

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