Let x be a random variable representing the mean weight of a one-year-old Hereford bull. Then
a.) P(x < 1100) = P (z < (X - mean)/sd) = P(z < (1100 - 1150)/80) = P(z < -0.625) = 1 - P(z < 0.625) = 1 - 0.73401 = 0.2660
b.) The middle (50%) of Hereford weights will weigh the mean weight of the sample. i.e. the middle (50%) of the Hereford weights will be 1150 pounds
Answer:4/5
Step-by-step explanation:
Because thats ehat i think
Answer:
x = 5
Explanation:
Subtracting 2 from both sides of the equation
17 − 2 = 3x +2 − 2
15=3x
Dividing both sides by 3
15/3 = 3x/3
5 = x
The answer you're looking for is 83.