Question

In □PQRS side PQ∥ side RS. If m∠P = 108degree

Answer 1

Answer:

Step-by-step explanation:

Given side PQ∥ side RS and

m∠P = 108degree

By sum of interior angles of parallel lines,

m∠S +  m∠P = 180degree

m∠ S = 180 - 108 = 72degree

Given m∠R = 53degree

By sum of interior angles of parallel lines,

m∠Q +  m∠R = 180degree

m∠Q = 180 - 53 = 127degree

Answer 2

Given :-

In □PQRS side PQ∥ side RS. If m∠P = 108degree

and m∠R = 53degree

To Find :-

m∠Q and m∠S.

Solution :-

According to angle sum property

P∠Q=180−∠P

∠Q=180−108

$\boxed{\sf{\angle Q = 72°}}$

For angle S

∠S=180−∠R

∠S=180−53

$\boxed{\sf {\angle S = 127°}}$

$\maltese\bold {lucky75} \maltese$