2 years ago

Which of the graphs below would result if you made the leading term of the

Mathematics

1 answer:

solong [7]2 years ago

4 0

Answer:

Step-by-step explanation:

It goes up and down due to the x^3 then the 3x^2

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -3 - 2 cos θ

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Im just guessing, is it no symmetry?

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2 years ago

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pav-90 [236]

Answer:

Step-by-step explanation:

Just stop taking 40 dollars out of the bank every week

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Find the function of which is the solution of 36y"-48y'-48y=0 with initial conditions y1(0)=1. y1'(0)=0

lilavasa [31]

Answer:

$y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }$

Step-by-step explanation:

Let, $D=\frac{d}{dx}$

Now, us simplify the given differential equation and write it in terms of D,

$36y''-48y'-48y=0$

or, $3y''-4y'-4y=0$

or, $(3D^2-4D-4)y=0$

We have our auxiliary equation:

$3D^2-4D-4=0$

or, $(3D+2)(D-2)=0$

or, $D=2, - \frac{2}{3}$

Therefore our solution is,

$y=Ae^{2x}+Be^{- \frac{2}{3}x}$

and, $y'=2Ae^{2x}-\frac{2}{3}Be^{\frac{2}{3}x }$

Applying the boundary conditions, we get,

$A+B=1$

$2A-\frac{2}{3}B=0$

Solving them gives us,

$A=\frac{1}{4} ,B=\frac{3}{4}$

Hence,

$y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }$

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3 years ago

The equation y = 1/4x represents a proportional relationship. What is the constant of proportionality?

Andrew [12]

Answer:

[see below]

Step-by-step explanation:

The equation is in the form:

y = kx

Where k is the constant of proportionality.

Since 1/4 is in k's spot, the constant of proportionality should be '1/4'.

Hope this helps.

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2 years ago

Pls help 25h²- 16t² factorise it

noname [10]

Answer:

(5h-4t)(5h+4t)

Step-by-step explanation:

25h² - 16t²

adding and subtracting 20ht from it (√25 and √16 = 5x4 = 20):

25h² + 20ht - 20ht -16t²

factor:

(5h-4t)(5h+4t)

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