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disa [49]
3 years ago
6

Solve for x over the complex numbers.

Mathematics
2 answers:
Grace [21]3 years ago
8 0

Answer:


Step-by-step explanation:

Given x^2+4x+13=0, find the complex roots.  The best approach here is to use the quadratic formula.  Note that a = 1, b = 4 and c = 13.  

Thus, the discriminant, b^2 - 4ac, is (4)^2 - 4(1)(13) = 16 - 52 = -36, and the square root of that is plus or minus i√36, or  plus or minus 6i.  


plus or minus i√

AysviL [449]3 years ago
8 0

Answer:

x = - 2 + 3i or x = - 2 - 3i

Step-by-step explanation:

Given quadratic equation,

x^2 + 4x + 13=0

By the quadratic formula,

x=\frac{-4\pm \sqrt{4^2 - 4\times 1\times 13}}{2\times 1}

x=\frac{-4\pm \sqrt{16-52}}{2}'

x=\frac{-4\pm \sqrt{-36}}{2}

x=\frac{-4\pm 6i}{2}

x=-2\pm 3i

Hence, the solution of the given equation,

x = - 2 + 3i or x = - 2 - 3i

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