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Sindrei [870]
4 years ago
11

Jane and Jillian are hiking around a hill and one complete circle is 8 miles long. They start together but hike in opposite dire

ctions. Both start to hike at 8:00 AM. Jane's hiking speed is 3 mph and Jillian's hiking speed is 5 mph. How long will it take before they meet? At what time will they meet? In how many hours? What time will they meet at?
Mathematics
1 answer:
Jlenok [28]4 years ago
3 0

Answer:

It will tale 1 hour before they meet and they will meet agin at 9 :00 AM.

Step-by-step explanation:

Speed of Jane, v_1=3 mph

and the speed of Jillian, v_2= 5 mph.

Length of one complete circle = 8 miles.

Both are moving in the opposite direction, let the starting point is at O, and met at the point P after time, t, as shown in the figure.

Let the length covered by Jane via path OAP= x miles.

\Rightarrow x= 3t [as distance= speed x time]

\Rightarrow t=x/3 \cdots(i)

The length covered by Jillian via path OBP = 8-x miles

\Rightarrow 8-x= 5t [as distance = speed x time]

\Rightarrow t=(8-x)/5 \cdots(i)

Now from equation (i) and (ii),

\frac{x}{3} = \frac{8-x}{3}

\Rightarrow 5x=3(8-x)

\Rightarrow 5x+3x=24

\Rightarrow x=3

So, the distanc covered by Jane = 3 miles and

the distanc covered by Jillian = 8-3=5 miles

From equation (i), time taken, t = 3/3= 1 hour.

So, it will tale 1 hour before they meet.

As the startion time was 8:00 AM, so the will agin meet at 9 :00 AM.

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