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3 years ago

The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is

Mathematics

2 answers:

madreJ [45]3 years ago

8 0

Answer: $5u^2v^2$

Step-by-step explanation:

Given monomials : $15u^2v^3, 20u^5v^2, 45u^3v^5$

We can rewrite the above monomials as product below :-

$15u^2v^3=5\times3u^2v^3\\\\ 20u^5v^2=5u^5v^2\times4\\\\45u^3v^5=5\times9u^3v^5$

Therefore, the greatest common factor for numerical coefficients of monomials = 5

Also, the greatest common power of u =2

and the greatest common power of v = 2

Hence, the greatest common factor of $15u^2v^3, 20u^5v^2, 45u^3v^5$ is $5u^2v^2$

goldfiish [28.3K]3 years ago

6 0

Hello here is a solution :
<span>The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is : 5u²v²</span>

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