Question

A bag contains 4 white, 3 blue, and 6 red marbles. A marble is drawn from the bag, replaced, and another marble is drawn. Find the probibility that.......​

Answer 1

First find the probability of each color being drawn.

We need to find the total number of marbles first.

4 + 3 + 6 = 13

So everything will be over 13.

Probability of a white marble being drawn --> $\frac{4}{13}$

Probability of a blue marble being drawn --> $\frac{3}{13}$

Probability of a red marble being drawn --> $\frac{6}{13}$

Now to find the probabilities of more than one being drawn, we can multiply.

Part a :

$\frac{6}{13}*\frac{6}{13}=\frac{36}{169}$

Part b :

$\frac{3}{13}*\frac{3}{13}=\frac{9}{169}$

Part c :

$\frac{6}{13}*\frac{3}{13}=\frac{18}{169}$

Part d :

$\frac{7}{13}*\frac{7}{13}=\frac{49}{169}$