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2 years ago

Use the graph below to answer the following questions.

Mathematics

1 answer:

Maru [420]2 years ago

3 0

Answer:

a) 3
b) x = {-3, -2, 2}

Step-by-step explanation:

Refer to attached for points

a) f(-1) = 3 as per graph

b) f(x) = 6

We add horizontal line through point y=6 to find intersections with the graph

Take x-values of those points. The points are x = -3, x = -2, x = 2

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Jacob and Mirit decide to race their pet snails. Jacob's snail moves 25 inches per minute, and Mirit's snail travels 28 inches p

sweet-ann [11.9K]

Answer:

180 inches

Step-by-step explanation:

25 inches per minute

in 1 hour (60 minutes) :

25*60 = 1500

28 inches per minute

in 1 hour (60 minutes) :

28 * 60 = 1680

1680-1500 = 180

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2 years ago

Tyler is mowing sand from his driveway to the backyard. The wheelbarrow weighs 30 kilograms when it is full of sand. When it is

Stells [14]

Tyler moved 180 kilograms
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2 years ago

Which expression is equivalent to -3 - (-5) *

horrorfan [7]

Where are the expression.
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2 years ago

Express the following as percentages. (i) 12 hours in 3 days

Zolol [24]

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2 years ago

Read 2 more answers

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

2 years ago

Use the graph below to answer the following questions.​

Use the graph below to answer the following questions.