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3 years ago

Which values from the given replacement set make up the solution set of the inequality? 2b≥6;

1 answer:

5 0

The answer is A because the variable can’t be no lower than 3 and every other answer has 2 in it. 2•(3) is equal to 6 and 2•(4) is greater than 6 which correlates with the sign (greater than or equal to).

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The product of this problem

Ganezh [65]

See my steps answer is -12

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3 years ago

3x+(2x-5)=13-2(x+2)how much is this

Dimas [21]

Look at the pictures it explains the equation step by step tell me if you have any questions the answer is at the bottom

3 0

3 years ago

Question 4 What is the value of 3 - 21-4 +32, ?

andrey2020 [161]

Answer:

Step-by-step explanation:

3-21-4+32

=-18-4+32

=-22+32

=10

8 0

3 years ago

Read 2 more answers

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

3 years ago

What does 3ˣ + 4·3ˣ⁺¹ = a. 13·3ˣ⁺¹ b. 5·3ˣ⁺¹ c. 5·3²ˣ⁺¹ d. 13·3ˣ

Crazy boy [7]

Answer:

D. 13*3^x

Step-by-step explanation:

$3^x +4*3^x^+^1= \\3^x+4*3(3^x)=\\3^x(1+[4*3])=\\3^x(1+12)=\\3^x(13)=\\13*3^x$

3 0

3 years ago