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SCORPION-xisa [38]

3 years ago

13

SOS I'm terrible at math.

1 answer:

Tresset [83]3 years ago

5 0

<span>y = -5 cos x is a basic (simple) variation of the basic trig function y = cos x.

The given </span>y = -5 cos x could be re-written as <span>y = -5 cos 1x.
Compare this to the most general form: y = a cos bx.

Here we see that the coefficient b equals 1.

There is a rule for finding the period of such a function: Period = 2pi/b.

Since b = 1 here, the Period here is 2pi/1, or simply 2pi.

Please stop saying "I'm terrible with math." That does not help you at all. Say, instead, "With just a little help I could understand this just fine."</span>

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Ashley will tend a car for the weekend.she can choose one of two plans.the first plan has an initial fee of $49.96 and cost an a

Rom4ik [11]

First, you multiply $55.96 by $0.12 and you get $6.7152. Then, multiply $49.96 by $0.14 and you get $6.9944. If you subtract $69944-$6.7152 you get your answer which is $0.2792.

5 0

3 years ago

Math problem need help plz

alexira [117]

Answer:

angle LXZ is 121°

Step-by-step explanation:

Since the sum of same side interior angles equals 180 you just subtract the angle you're given from 180 (180°-59°=121°)

6 0

2 years ago

Can someone help me with this math homework please!

azamat

It is not necessary that the function decreasing over a given interval always be negative.

A function f(x) (value) decreases as x increases.

This does not mean that value of f(x) is negative.

It can have positive number as range.

7 0

2 years ago

Read 2 more answers

One angle of a triangle measures <img src="https://tex.z-dn.net/?f=10degrees" id="TexFormula1" title="10degrees" alt="10degrees"

iVinArrow [24]

Answer:

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

$x+y+z=180^o$ -----> equation A

One angle of a triangle measures 10 degrees more than the second

$x=y+10$ ----> equation B

The measure of the third angle is twice the sum of the first two angles

$z=2(x+y)$ ---> equation C

substitute equation B in equation C

$z=2(y+10+y)$

$z=4y+20$ ----> equation D

substitute equation D and equation B in equation A

$(y+10)+y+(4y+20)=180^o$

solve for y

$6y=180-30\\6y=150\\y=25^o$

Find the value of x

$x=25+10=35^o$

Find the value of z

$z=4(25)+20=120^o$

therefore

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

5 0

3 years ago

If f(x) = 10 + 50x, solve for x when f(x) = 310.

weqwewe [10]

x = 6

given f(x) = 310, we obtain the equation

10 + 50x = 310 ( subtract 10 from both sides )

50x = 300 ( divide both sides by 50 )

x = $\frac{300}{50}$ = 6

5 0

3 years ago