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SCORPION-xisa [38]

4 years ago

13

SOS I'm terrible at math.

1 answer:

Tresset [83]4 years ago

5 0

<span>y = -5 cos x is a basic (simple) variation of the basic trig function y = cos x.

The given </span>y = -5 cos x could be re-written as <span>y = -5 cos 1x.
Compare this to the most general form: y = a cos bx.

Here we see that the coefficient b equals 1.

There is a rule for finding the period of such a function: Period = 2pi/b.

Since b = 1 here, the Period here is 2pi/1, or simply 2pi.

Please stop saying "I'm terrible with math." That does not help you at all. Say, instead, "With just a little help I could understand this just fine."</span>

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(Fog) (x) f(x)=6x-5 <br> g(x) =6x^2-3x

algol [13]

Answer:

see below

Step-by-step explanation:

put g(x) in for the x in f(x)

$f(x)= 6x-5\\g(x)= 6x^{2} -3x\\f(g(x)= 6(6x^{2} -3x)-5$

5 0

3 years ago

i know this is probably simple but ive forgotten how to do it and i cant find it in my notes help appreciated!

Soloha48 [4]

Answer:

? = 13.6

Step-by-step explanation:

the angle between a tangent and the diameter = 90°

Then the triangle is right with legs 2 × 6 = 12 and 6.4

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the legs , that is

? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )

? = $\sqrt{184.96}$ = 13.6

6 0

2 years ago

Fully simplify 7c - 4h - 2c - 5h

astraxan [27]

Answer:

5c-9h

Step-by-step explanation:

1) 7c-4h-2c-5h

2) 5c-4h-5h

3) 5c-9h

4 0

2 years ago

Multiply and simplify if possible

ad-work [718]

Answer:

6 √ ( 3 x + 5 ) ( 3 x − 2 )

Step-by-step explanation:

3 0

4 years ago

Please help me I need help please

MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

<u>Standard equation of a circle:</u>

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

$\implies p=1+3=4$

<u>Additional information</u>

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

$\implies x^2-4x+y^2+6y=16$

$\implies (x-2)^2-4+(y+3)^2-9=16$

$\implies (x-2)^2+(y+3)^2=16+4+9$

$\implies (x-2)^2+(y+3)^2=29$

So this is a circle with centre (2, -3) and radius √29

3 0

2 years ago