Let A unit be a; B unit be b
a + b = 95
b = 95 - a
3a + 5b = 395
3a + 5(95 -a) = 395
3a + 475 - 5a = 395
-2a = -80
a = 40
a + b = 95
40 + b = 95
b = 55
Therefore, a = 40; b = 55.
Hope this helps
Answer:
The new mean for the exam scores is 51
Step-by-step explanation:
the mean can be calculated using the formula
mean of scores = 
before the 20 points was added, the mean of the score was = 50.
Inserting this into the formula, we have:
50 = 
from this, we can compute the sum total of the scores as
sum total = 50 × 20 = 1000
when the extra 20 marks is added, the sum of the entire scores will be changed to 1000 + 20 = 1020.
Hence the new mean will be computed as (New Sum total of scores / Number of students)
=
= 51.
∴ The new mean of the scores is = 51
Y=1/3x while m=0................
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I hope this helps you
EF=FG
6x-4=5x+7
x=11
Answer:
4845 combinations
Step-by-step explanation:
Whenever there is a selection of some elements from a certain group, there are several ways to do so. There are different combinations from the group which can be selected. The concept of combination means that there are certain number of elements to be selected from the group and there is no importance given to the order of the selection. The total number of students are 20, and 4 out of them have to be selected. It can be clearly seen that the order of selection does not matter, therefore the formula to be used is:
Combinations = 20C4 = (20*19*18*17)/(4*3*2*1) = 4845.
So the correct answer is 4845 combinations!!!