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3 years ago

Graph Y= 1/3x {If someone could help me on this I would really appreciate it}

Mathematics

2 answers:

sergeinik [125]3 years ago

8 0

This equation y = x/3 is in for off y = mx+b
it has slope(m) = 1/3 and y-intercept (b) = 0.
as b = 0 the origin would be (0,0) now use m to find the 2nd point.
slope = y/x = rise /run = 1/3
move up 1 and right 3 and you get point (3,1)
connect the two dots and you have your graph.

gizmo_the_mogwai [7]3 years ago

7 0

Y=1/3x while m=0................

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Ipatiy [6.2K]

In this question we know what the “y-intercept is,so if we go to our graph we can easily just plot the point 7.6 on the y axis of a number line. It also gives you the slope in decimal form so we would want to convert that from 0.2 to 1/5. And remember the slope is how many places you move to get to the next point on the number line. So from the point 7.6 we would move up 1 over 5 to the right because it is a positive number. Your line should run across the upper segment of the number line and your line should make a 20 to 30 degree angle shift

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4 years ago

The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the h

Mama L [17]

The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively

<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3>

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft) h(ft)

0 2.5

50 25

100 42.5

150 55

200 62.5

250 65

300 62.5

350 65

400 42.5

See attachment for the graph of Juan's function

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

<u>Barry</u>

From the graph, we have the table of values of Barry's function to be:

d (ft) h(ft)

0 2.5

50 21

100 35

150 44

200 48

250 46

300 41

350 30

400 14

450 0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

<h3>The height the balls hit a fence at 350 ft distance</h3>

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

Read more about quadratic functions at:

brainly.com/question/12446886

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2 years ago

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valentinak56 [21]

Answer:

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Step-by-step explanation:

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Please mark as brainliest :)

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4 years ago

Five members of the soccer team ordered orange juice. Ten members ordered apple juice. Juice was packaged in 250 mL cartons. Exp

Lady_Fox [76]

The answer to the question is B

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3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

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3 years ago