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jekas [21]
3 years ago
11

suppose 8 out of every 20 students are absent from school less than 5 days a year predict how many students would be absent from

school less than five days a year out of 40,000 students
Mathematics
1 answer:
Liula [17]3 years ago
4 0
40,000 divided by 20 = 500
500 x 12 (which was 20-8)= 6,000
6,000 students
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Can someone please explain #7 to me
sergeinik [125]

Answer:

$28

Step-by-step explanation:

You subtract $44 from $100 since that is the cast of the jeans. Then get left remaining with $56. Since he wants to buy 2 shirts only you divide 56 by 2 to then equaling $28. So then each shirt is $28.

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1.  Lisa is working with the system of equations x + 2y = 7 and 2x ‒ 5y = 5. She multiplies the first equation by 2 and then sub
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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
What is the median of the data set: {24, 31, 12, 38, 12, 15}A)12B)19.5C)24D)23.5
QveST [7]

Answer: B: 19.5

Step-by-step explanation:

This data set is an even data set meaning that you're going to have to add and divide, so you put your data set in ascending order (highest # to lowest #) so 12,12,15,24,31,38 its an even data set so you're going to put them in groups (remember your finding the median, the middle numbers) so you have 12,12 (one group) and 31,38 (another group) (basically make it even!!) so now you're left with the middle numbers, you have to add them and then divide them by 2 so (15+24) ÷2 and you get your answer !!

6 0
2 years ago
I really need help with this question I’m taking a test it’s urgent !!
dimaraw [331]

Answer:

EF = 10

Step-by-step explanation:

QUICK

9/15 = 6/x

x=10

8 0
3 years ago
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