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I am Lyosha [343]
3 years ago
11

Problem PageQuestion Flying against the jetstream, a jet travels 3050 miles in 5 hours. Flying with the jetstream, the same jet

travels 3800 miles in 4 hours. What is the rate of the jet in still air and what is the rate of the jetstream?
Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Answer: the rate of the jet in still air is 685 mph and the rate of the jetstream is 75 mph

Step-by-step explanation:

Let x represent the rate of the jet in still air.

Let y represent the rate of the jet jetstream.

Distance = speed × time

Flying against the jetstream, a jet travels 3050 miles in 5 hours. This means that the total speed of the jet would be (x - y) mph. Therefore,

3050 = 5(x - y)

3050/5 = x - y

x - y = 610 - - - - - - - - - - - - - -1

Flying with the jetstream, the same jet travels 3800 miles in 4 hours. This means that the total speed of the jet would be (x + y) mph. Therefore,

3800 = 4(x + y)

3800/5 = x + y

x + y = 760 - - - - - - - - - - - - - -2

Adding equation 1 to equation 2, it becomes

2x = 1370

x = 1370/2 = 685mph

Substituting x = 685 into equation 1, it becomes

685 - y = 610

y = 685 - 610 = 75mph

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Answer:

104

Step-by-step explanation:

This is not a distributive property question though.

A distributive property has a number (a) outside the parenthesis

a(b+c)

so in this case a(40+64)

then you would multiply a by both numbers

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then add them together

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However if it is a number outside the parenthesis and not a variable, it will come out different

For example

5(40+64)

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520

Hope this helps!

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Find the point, M, that divides segment AB into a ratio of 3:2 if A is at (0, 15) and B is at (20, 0).
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5 0
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Find the multiplicative inverse of 6 + 2i
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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2774989

________________


Find the multiplicative inverse of

\mathsf{z=6+2i}

________


The inverse multiplicative of  \mathsf{z=a+bi}  is

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\&#10;=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}

=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\&#10;\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}

________


For this question,

\mathsf{z=6+2i}


So,

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{6+2i}}\\\\\\&#10;=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}


\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

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