I think you're right. I'm in pre-algebra, and sucks at it. Yet, I keep a A.
Answer:-2
Step-by-step explanation:
Log3(1/9)
Log(1/9) ➗ Log3
Log(1/3^2) ➗ Log3
Log3^(-2) ➗ Log3
-2Log3 ➗ Log3
-2(Log3 ➗ Log3)
-2
Answer:
25/28
Step-by-step explanation:
28 is the greatest common factor, found by multiplying 7 by 4 (the denominators)
1/7 = 4/28
3/4 = 21/28
21/28 + 4/28 = 25/28
Answer:
-7, -6, -5, -4, -3
Step-by-step explanation:
Given:
2x + 5 < 0
x > -8
Thus, we can combine both statements to find out integers that satisfy both inequalities.
2x + 5 < 0
Let's find x
2x < 0 - 5 (substraction property)
2x < -5
Divide both sides by 2
x < -5/2
This implies that -5/2 is greater than the set of values of x.
The second inequality, x > -8 implies that -8 is less than the value of x.
Les combine both:
-8 < x < -5/2
Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.
Thus, they are:
-7, -6, -5, -4, -3