Log6(5-2a)-log6(3a)=1
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Let's build the equation counting how many x's and 1's are there on each side.
On the left hand side we have 5x's and 8 1's, for a total of
On the left hand side we have 3x's and 10 1's, for a total of
So, the equation we want to solve is
Subtract 3x from both sides:
Subtract 8 from both sides:
Divide both sides by 2: