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NeX [460]
3 years ago
14

HELP!! I NEED THIS QUICKLY

Mathematics
1 answer:
Elza [17]3 years ago
6 0

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

x_1=\frac{3}{4}

y_1=\frac{2}{3}

x_2=\frac{1}{4},y_2=1

x_3=1,y_3=\frac{1}{2}

x_4=\frac{1}{2},y_4=1

k=\frac{1}{2}

Direct proportion:

\frac{x}{y}=k

Inverse proportion:xy=k

\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}

Therefore, it is not in direct proportion.

\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}

\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}

x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}

x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}

x_3y_3=1\times \frac{1}{2}=\frac{1}{2}

x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}

Therefore, xy=k=\frac{1}{2}

Hence, the given points form an inverse variation .

xy=\frac{1}{2}

y=\frac{1}{2x}

Option A and D is true.

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An extraneous solution is a solution that isn't valid, it might be imaginary like the square root of a negative number.

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