Question

HELP!! I NEED THIS QUICKLY

Answer 1

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

$x_1=\frac{3}{4}$

$y_1=\frac{2}{3}$

$x_2=\frac{1}{4},y_2=1$

$x_3=1,y_3=\frac{1}{2}$

$x_4=\frac{1}{2},y_4=1$

k=$\frac{1}{2}$

Direct proportion:

$\frac{x}{y}=k$

Inverse proportion:$xy=k$

$\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}$

Therefore, it is not in direct proportion.

$\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}$

$\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}$

$x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}$

$x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}$

$x_3y_3=1\times \frac{1}{2}=\frac{1}{2}$

$x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}$

Therefore, $xy=k=\frac{1}{2}$

Hence, the given points form an inverse variation .

$xy=\frac{1}{2}$

$y=\frac{1}{2x}$

Option A and D is true.