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deff fn [24]
3 years ago
11

Melinda Randolph bought 1,500 shares of Huge Corporation stock for $155,250. She sold the stock for $101 per share and paid a sa

les commission of $39. What is the profit or loss from the sale? (Enter the dollar amount followed by a space and the word loss or profit.)
Can someone help me?
Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

3789.00 loss

Step-by-step explanation: Well She sold the stock but for every stock she sold she had to pay commission which was 39 Dollars for every stock sold. She only Made 2.5% of the Stocks sold, Which is an L, So the answer would be 3789.00, Loss.

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On what interval is the functioning decreasing m(x)=4x^3-5x^2-7x?
Verdich [7]
M(x) = 4x^3 - 5x^2 - 7x
Let us first find the zeros of the function.
That is when it is equal to zero.

m(x) = 4x^3 - 5x^2 - 7x  = 0
x(4x^2 - 5x - 7) = 0.  Therefore x = 0 or 4x^2 - 5x - 7 = 0.
Using a quadratic function calculator to solve 4x^2 - 5x - 7
x = 2.09, -0.84
Therefore the zeros are x =-0.84, 0, 2.09 for the function m(x).

The intervals observed are imagining  that the zeros are on the number line:
x<-0.84,    -0.84<x<0,  0<x<2.09,  x>2.09.

For each of this range we would test the function with a number that falls in the range.

The function is decreasing in the interval where it is less than 0.
For x<-0.84, let us test x = -1, m(x) = 4x^3 - 5x^2 - 7x = 4(-1)^3 - 5(-1)^2 - 7(-1) = -4 -5 +7 = -2,    -2 < 0, so it is decreasing here.

For  -0.84<x<0, let us test x = -0.5, m(x) = 4x^3 - 5x^2 - 7x = 4(-0.5)^3 - 5(-0.5)^2 - 7(-0.5) = -0.5 -1.25 +3.5 = 1.75,  1.75 >0. It is not decreasing.


For  0<x<2.09, let us test x = 1, m(x) = 4x^3 - 5x^2 - 7x = 4(1)^3 - 5(1)^2 - 7(1) = 4 -5 -7 = -8,  -8 <0. It is decreasing.

For  x>2.09, let us test x = 3, m(x) = 4x^3 - 5x^2 - 7x = 4(3)^3 - 5(3)^2 - 7(3) = 108 -45 -21 = 42,  42 >0. It is not decreasing.

So the function is decreasing in the intervals:

x < -0.84,  & 0<x<2.09.

4 0
3 years ago
Which of the following functions best describes this graph? Will give brainliest to the most detailed answer!
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Answer:

c) im pretty sure

Step-by-step explanation:

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Four rectangles have the following dimensions:
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Rectangle A ~ Rectangle B
5 0
3 years ago
A rectangle is 4xcm wide and 2cm long what do you notice
deff fn [24]

The width of the rectangle is twice the length of the rectangle

<h3>How to compare the dimensions of the rectangle?</h3>

The given parameters are:

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Substitute Length = 2 cm in Width = 2 * 2 cm

Width = 2 * Length

This means that the width of the rectangle is twice the length of the rectangle

Hence, the true statement is that the width of the rectangle is twice the length of the rectangle

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Step-by-step explanation:

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