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2 years ago

The circumference of a circle is 6.28 millimeters. What is the circle's radius?

Mathematics

1 answer:

Aleksandr [31]2 years ago

6 0

Circumference of a circle =2πr

6.28=2πr

3.14=πr

3.14/π=r

3.14/3.14=r

<h2>therefore,r=1</h2>

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If n(A) = P and n(B)=q then n(AxB) is (a ) p (b ) q ( c ) p+q ( d ) pq

Butoxors [25]

By way of example, suppose A = {1, 2, 3} and B = {a, b, c}. Then the Cartesian product of A and B is

A × B = {{1, a}, {1, b}, {1, c}, {2, a}, {2, b}, {2, c}, {3, a}, {3, b}, {3, c}}

That is, each element in A gets a pairing with each element in B, and for each pairing you have n(A) choices for the first element and n(B) choices for the second element.

So if n(A) = p and n(B) = q, then n(A × B) = pq.

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3 years ago

I need to paint a bin rectangular bin w no top... bin length is 25mm and width of 9 mm how much paint do I need to cover bin

Nikitich [7]

Answer:

900mm of paint for all four sides

Step-by-step explanation:

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3 years ago

Find the linearization L(x) of the function at a. f(x) = x3/4, a = 81

Zolol [24]

Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.

If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is

f(x) approx. equal to [f '(c)]x + f(c)].

Here a = c = 81.

Thus, the linearization of the given function at a = c = 81 is

f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4

Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.

What is the linearization of f(x) = (x^3)/4, if c = a = 81?

It will be f(x) (approx. equal to)

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3 years ago

Suppose planet A's diameter is approximately 8 times planet B's and both bodies are spheres. What is the ratio of their volumes?

lana [24]

Answer:

The ratio of planet B's volume to planet A's volume is 1:512 or 1/512

Step-by-step explanation:

Volume of sphere = 4/3 π r^3

r = d/2

Radius of palnet A = 8/2 = 4

Radius of planet B = 1/2

Since 4/3 π is same in both volumes so, they cancel out when finding ratio.

Now ratio depends on radius cube of both planets

Volume of Planet B : Volume of Planet A

4/3 π(1/2)^3 : 4/3 π(4)^3

Cancelling 4/3 π on both sides

1/8 : 64

Multiply 8 on both sides

1 : 512

So, The ratio of planet B's volume to planet A's volume is 1:512 or 1/512

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3 years ago

The pyramid shown has a square base that is 18 inches on each side. It has a surface area of 864 square inches. What is the slan

disa [49]

The first step is to find the relationship between the square base and the surface area.

Surface area (SA) = area of the square (SS) + area of triangles.4(AT)

Thus we can conclude area of triangles 4(AT) = SA - SS = 864 - (18*18)

4(AT) = 864 - 324 = 540

Each triangle = 540/4 = 135 square in.

An area of one triangle (AT)= (base* slant height)/2

The base = 18 in.

slant height = 2(AT)/base = 2(135)/18 = 15

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3 years ago